2^4x-7=2^2x+1

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Solution for 2^4x-7=2^2x+1 equation: 



2^4x-7=2^2x+1

We move all terms to the left:

2^4x-7-(2^2x+1)=0

We get rid of parentheses

2^4x-2^2x-1-7=0

We add all the numbers together, and all the variables

2^4x-2^2x-8=0

We move all terms containing x to the left, all other terms to the right

2^4x-2^2x=8

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